Again, this is from io9's site: http://io9.com/this-weeks-puzzle-is-as-easy-as-pie-1687313362
Sunday Puzzle #21: Slicing Pie
One straight slice through one whole pie divides the pie into two pieces. Simple enough. A second straight cut, crossing the first, will produce four pieces. A third cut, directed through the intersection of the first two, will make six pieces –but a third slice, strategically placed, can actually create as many as seven pieces. What is the maximum number of pieces you can produce with six straight cuts? With N straight cuts?
I would think N straight cuts would end in infinity. As far as 6, would it be something like (2n +1) = y. Hmm, no that can't be right. What do you guys think?
7/3 = X/6 | X= 14?
Seems too simple though...
N straight cuts either matters on the size of the pie or just goes to infinite.
I'm thinking 22? Or for n: ½(n² + n + 2). That is, if I'm correct in assuming the maximum number of pieces for four slices is 11, five is 16, and so on.
That sounds pretty good. Where did you get the n squared from?
1 + Σn as a partial sum formula is 1 + (½n(n + 1)). The square comes from the n being multiplied by n + 1.
You were RIGHT! Good work.
I did this a few years ago in Maths, the answer will come to me eventually.
Thinking in only two dimensions, three cuts could get you seven slices; but thinking three dimensionally you can get eight. I believe that @BradinDvorak's solution might be the correct answer to this puzzle, but the more slicing planes you use and the more dimensions to which you have access the more pieces you can get.
It's all in how you slice it...
Pretty sure you were on the right track only, |2n+1|=y so you can't come up with a negative number
I'm not sure. Sigma being the sum of?
You are right, too, good strong work.
... Can't I just eat the pie? ^_^
Yes. Yes you can. ;D
I like pie
I kind of dislike this puzzle, as it is not really a puzzle or a riddle. It's just an advanced math test, and I seem to remember something similar actually BEING on a math test I did once.
The previous ones required logical thinking and deduction. This simple requires math, so if you are great with advanced math it is easy, if you are not it is impossible.
I agree with briar rose. Lets just eat the pie
Shit I just remembered about this, let's check the answer.
The answer is basically the n+1 in that, yes, the answer would be 22. But the total could be infinity. EDIT: No, it's not. That's why n+1 is wrong.
Mathematician in the comments arguing about infinity:
The real question is 'what is a quantum slice of pizza?' Mathematically, you can do this to infinity but given a normal 14" pizza at some n your smallest slice will be smaller than the plank length and non-measurable. Can you slice a pizza so small that God cannot make it? Anyway ...
f(1)=2, f(2)=4, f(3)=7, f(4)=11, f(5)=16, f(6)=22, f(7)=29.
It it technically possible, though aesthetically ugly to use each new straight cut to cut through all the other straight cuts. That's how you get 7 slices with 3 cuts, the third goes through the 2 other lines. You get 11 slices with a fourth cut that goes through the previous 3 cuts.
So I think that's
F(n)=(Σ(1,n) n) +1
Here's the explanation:
Let n be the number of straight cuts to be made on a 2D pie, then the number of slices can be given by:
Slices=No.of touchpoints+(No.of intersections-previous lines) where
No.of touchpoints=No.of cuts*2 (points where the lines touch the circumference)
No.of intersections=No.of points within the pie where 2 lines cross each other
No.of previous lines=n-1
and No.of intersections=(n-1*(n))/2
The closed form function= (n*2)+((n*(n-1)/2)-(n-1))
This thread is a month old, but... I suppose we can let this necro slide because this sounds like it's right.
EDIT: Nvm, madglee posted the answer or something a while back..
It is right.
Ah, mmkay. Besides, madglee posted the answer a while back.